X^2=2y/8

Solution for X^2=2y/8 equation:

X^2=2X/8

We move all terms to the left:

X^2-(2X/8)=0

We add all the numbers together, and all the variables

X^2-(+2X/8)=0

We get rid of parentheses

X^2-2X/8=0

We multiply all the terms by the denominator


X^2*8-2X=0

Wy multiply elements

8X^2-2X=0

a = 8; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·8·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*8}=\frac{0}{16}
=0
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*8}=\frac{4}{16}
=1/4
$